Question

If Rolle’s theorum holds for the

Answer 1

Step-by-step explanation:

f(x)=2x3+bx2+cx and x∈[−1,1]

For rolles theorem to be applicable f(1)=f(−1) and f′(21)=0

f(1)=f(−1)

⇒2+b+c=−2+b−c⇒c=−2

and f′(21)=0

⇒6(21)2+2b(21)+c=0⇒23+b−2=0⇒2b=1

Hence 2b+c=−1