Question

if root 125 =k root 5 then k+2=​

Answer 1

${\huge{\underline{\underline{\tt{Answer\checkmark}}}}}$

☆ Given -

$\mapsto \: \sqrt{125} = k \sqrt{5}$

☆ To Find -

$\longrightarrow \: \rm{the \: value \: of \: (k + 2)}$

☆ Solution -

$\longrightarrow\sqrt{125} = \sqrt{5 \times 5 \times 5} = 5 \sqrt{5}$

but ,

$\longrightarrow \: \sqrt{125} = k \sqrt{5}$

so ,

compare both of them..

$\longrightarrow \: k \sqrt{5} = 5 \sqrt{5} \\ \\ \implies \: k = 5$

So , now ,

$\leadsto \: k + 2 = 5 + 2 = 7$

${\huge{\boxed{(k\,+\,2)\,=7}}}$

Answer 2

Answer:

Root of 125=K ROOT THEN K+2

Step-by-step explanation:

125ROOT =15×5=75+2=77-5=73Answer plz follow me plz and click Brainlit