Question

If root 2 is equal to 1.414 and root 5 is 2.236 and root3 is 1.732 thenfind root 72 +root 48

Answer 1

Heya !!!

$\sqrt{72} + \sqrt{48} \\ \\ = \sqrt{2 \times 2 \times 2 \times 3 \times 3} + \sqrt{2 \times 2 \times 2 \times 2 \times 3} \\ \\ = \sqrt{ {2}^{2} \times {3}^{2} \times 2 } + \sqrt{ {2}^{2} \times {2}^{2} \times 3 } \\ \\ = 3 \times 2 \sqrt{2} + 2 \times 2 \sqrt{3} \\ \\ = 6 \sqrt{2} + 4 \sqrt{3} \\ \\ = 8.484 + 6.928 \\ \\ = 15.412$

Hope this helps ☺