Question

If root 2 is equal to the 1.73 then find the value of subroot root 2+1/roo t2-1

Answer 1

$\frac{ \sqrt{2} + 1 }{ \sqrt{2} - 1} \\ \\ = \frac{ \sqrt{2} + 1 }{ \sqrt{2} - 1} \times \frac{ \sqrt{2} + 1 }{ \sqrt{2} + 1} \\ \\ = \frac{ { \big( \sqrt{2} + 1 \big) }^{2} }{ {( \sqrt{2} \: ) }^{2} - {1}^{2} } \\ \\ = \frac{ {( \sqrt{2} ) }^{2}+ 2 \times \sqrt{2} \times 1 + {1}^{2} }{2 - 1} \\ \\ = \frac{2 + 2 \sqrt{2} + 1}{1} \\ \\ = 3 + 2 \sqrt{2} \\ \\ = 3 + 2 \times 1.73 \\ \\ = 3 + 3.46 \\ \\ = 6.46$

Answer 2

Answer:

→ $\Huge{6.46}$

Step-by-step explanation:

$\begin{lgathered}\frac{ \sqrt{2} + 1 }{ \sqrt{2} - 1} \\ \\ = \frac{ \sqrt{2} + 1 }{ \sqrt{2} - 1} \times \frac{ \sqrt{2} + 1 }{ \sqrt{2} + 1} \\ \\ = \frac{ { \big( \sqrt{2} + 1 \big) }^{2} }{ {( \sqrt{2} \: ) }^{2} - {1}^{2} } \\ \\ = \frac{ {( \sqrt{2} ) }^{2}+ 2 \times \sqrt{2} \times 1 + {1}^{2} }{2 - 1} \\ \\ = \frac{2 + 2 \sqrt{2} + 1}{1} \\ \\ = 3 + 2 \sqrt{2} \\ \\ = 3 + 2 \times 1.73 \\ \\ = 3 + 3.46 \\ \\ = 6.46\end{lgathered}$