Question

if root 2 + root 3/3root2-2root3 = a-b root 6 , find a,b​

Answer 1

Answer:

a and B =34 as they are having root

Answer 2

Answer:

LHS = ( √2 + √3 )/(3√2-2√3)

= [(√2+√3)(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]

=[6+2√6+3√6+6]/[(3√2)²-(2√3)²]

= [12+5√6]/[18-12]

= ( 12 + 5√6 )/6

= 12/6 + 5√6/6

= 2 + (5/6)√6 ---( 1 )

= a + b√6-------( 2 )

Compare ( 1 ) and ( 2 ) , we get

a = 2 , b = 5/6