Question

if root 2 sin(60-A) = 1 then the value of A is​

Answer 1

Answer:

The answer is $15^\circ$

Step-by-step explanation:

Given  $\sqrt 2\sin(60^\circ-A)=1$

          $\displaystyle \Rightarrow \sin(60^\circ-A)=\frac{1}{\sqrt 2}\\\Rightarrow 60^\circ-A=45^\circ\\\Rightarrow A=60^\circ-45^\circ=15^\circ$

(Since we know that $\displaystyle \sin 45^\circ=\frac{1}{\sqrt 2}$ )

Answer 2

Given :

$\implies \sf \: \sqrt{2} \: sin(60 \degree - a \: ) = 1$

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To Find :

Alpha =?

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Solution :

~ Formula Used :

◆ Alpha = R – Rf – beta (Rm-Rf)

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$\implies \sf \: \sqrt{2} \: sin(60 \degree - a \: ) = 1$

$\implies \sf \: {2} \: sin(60 \degree - a \: ) = \frac{1}{ \sqrt{2} }$

$\implies \sf \: {2} \: sin(60 \degree - a \: ) = sin \: 45 \degree$

$\implies \sf \: \: a = 15 \degree$

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~ Therefore :

❛❛ Hence,The Alpha Is 15° ❜❜

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