If root 2 sin theta = 1 . Find the value of sin theta + sin 2 theta
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(Sqr2)sin(theta)=1
Sin(theta)=1/sqr2
So,theta=45 degrees
And cos(theta) =(square root of 2)/2=1/sqr2
Sin(2theta)=2sin(theta)cos(theta)=2(1/sqrt2)(sqrt2/2)=1
So,sin(theta)+sin(2theta)=1/sqr2+1=(sqrt2+1)/sqrt2
Sin(theta)=1/sqr2
So,theta=45 degrees
And cos(theta) =(square root of 2)/2=1/sqr2
Sin(2theta)=2sin(theta)cos(theta)=2(1/sqrt2)(sqrt2/2)=1
So,sin(theta)+sin(2theta)=1/sqr2+1=(sqrt2+1)/sqrt2
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