If root 2 X + 3 y + 5 = 0,Kx+ 65 + 7 = 20 are parallel then the value of k is
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Let 2x + 3y +5 = 0 ( equation 1 )
kx + 65 + 7 = 20 ( equation 2 )
2x + 3y +5 =0
2x + 3y = -5
5xy = -5
xy = -5/5
xy = -1
kx + 65 + 7 =20
k x -1 +65 +7 = 20
- k = 20-65-7
- k = -38
k= 38
hence the value of.. k is 38
kx + 65 + 7 = 20 ( equation 2 )
2x + 3y +5 =0
2x + 3y = -5
5xy = -5
xy = -5/5
xy = -1
kx + 65 + 7 =20
k x -1 +65 +7 = 20
- k = 20-65-7
- k = -38
k= 38
hence the value of.. k is 38
Answered by
0
Given two equations -
2x + 3y + 5 = 0
kx + 6y + 7 = 20 ______( 1 )
On further solving ( 1 )
kx + 6y + 7 - 20 = 0
kx + 6y - 13 = 0
a1 = 2, a2 = k, b1 = 3, b2 = 6, c1 = 7, c2 = - 13
Condition for parallel lines -
a1 / a2 = b1 / b2
Putting values
2 / k = 3 / 6
2 / k = 1 / 2
k = 2 × 2
k = 4
^^'
2x + 3y + 5 = 0
kx + 6y + 7 = 20 ______( 1 )
On further solving ( 1 )
kx + 6y + 7 - 20 = 0
kx + 6y - 13 = 0
a1 = 2, a2 = k, b1 = 3, b2 = 6, c1 = 7, c2 = - 13
Condition for parallel lines -
a1 / a2 = b1 / b2
Putting values
2 / k = 3 / 6
2 / k = 1 / 2
k = 2 × 2
k = 4
^^'
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