Math, asked by Vraj52, 7 months ago

If root 3 and minus( - )root 3 are the zeroes of x^4- x^3- 5x^2+3x + 36 then find all other zeroes.

Pls give explanation and answer

Answers

Answered by ayushyadav143
4

Answer:

Step-by-step explanation:

P(X) x⁴+x³-9x²-3x+18

Zeros are: √3, -√3

Factor of zeros are ( x-√3 ), ( X+√3 )

(X)²- (√3)²

X²-3 is a factor

: Division:

X²-3) x⁴+x³-9x²-3x+18( x²+x-6

X²+0x-3x

_______

X³-6x-3x+18

X³+0x-3x

________

-6x²+18

-6x²+18

______

0

_______

Remainder is : x²+x-6

X²+x-6( middle term spitting )

X²+x-6

X²-2x+3x-6

X(x-2)3(x-2)

(X+3)(x-2)

X+3=0, x-2=0

X=-3, X=2

Other zeros are 2,-3 and

Answered by topper05
1

Answer: The remaining zeros are -1 and 2. Step-by- step explanation: The given polynomial is. P(x)=

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