Math, asked by shlokkharva, 7 months ago

if root 3 and - root 3 are the zeroes of x⁴+4x³-8x²-12x+15 find its all zeroes​

Answers

Answered by krish9845123
1

Answer:

1,-5 are the remaining zeros

As √3, -√3 are zeros

x=√3 and x=-√3

therefore (x-√3) and (x+√3) are factors of equation that means (x-√3)(x+√3) is also a factor of the equation

now, we do ( x^4+4x^3-8x^2-12x+15 )÷{(x-√3)(x+√3)} to get other factor of equation which is x^2+4x-5 On solving this we get x=1 and x=-5

#KRISHHERE

MARK AS BRAINLIEST AND GIVE THANKS

Similar questions