if root 3 and - root 3 are the zeroes of x⁴+4x³-8x²-12x+15 find its all zeroes
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1,-5 are the remaining zeros
As √3, -√3 are zeros
x=√3 and x=-√3
therefore (x-√3) and (x+√3) are factors of equation that means (x-√3)(x+√3) is also a factor of the equation
now, we do ( x^4+4x^3-8x^2-12x+15 )÷{(x-√3)(x+√3)} to get other factor of equation which is x^2+4x-5 On solving this we get x=1 and x=-5
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