if root 3 cot square theta minus 4 cot theta + root 3 is equal to zero then find the value of cot square theta + tan square theta
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Step-by-step explanation:
Given if root 3 cot square theta minus 4 cot theta + root 3 is equal to zero then find the value of cot square theta + tan square theta
- Now √3 cot^2 theta – 4 cot theta + √3 = 0
- Now this is in the form of a quadratic equation and we have the formula
- So x = - b + - √b^2 – 4ac / 2a
- So cot theta = 4 + - √4^2 – 4√3 √3 / 2 √3
- = 4 + - √16 – 12 / 2√3
- = 4 + - √4 / 2√3
- = 4 + - 2 / 2√3
- = 6 / 2√3, 2 / 2√3
- Or we get cot theta = √3, 1 / √3
- Now cot^2 theta = 1/3, 3
- So tan^2 theta = 1/cot^2 theta
- = 1/1/3
- = 3
- Also tan^2 theta = 1/3
- So we have 1/3,3 and 3, 1/3
- So we get cot^2 theta + tan^2 theta = 3 + 1/3 = 10/3
Reference link will be
https://brainly.in/question/7799054
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Answer:
10/3will be the correct answer
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