if root 3 sin theta is equal to cos theta find the value of sin theta X tan theta X 1 + cos theta upon sin theta + cos theta
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√3sin@=cos@,
sin@/cos@=1/√3,
tan@=1/√3,
tan@=tan30°,
then
@=30°,
therefore
(sin@×tan@×1+cos@)/(sin@+cos@),
(sin30°×tan30°×1+cos30°)/(sin30°+cos30°),
(1/2×1/√3+√3/2)/(1/2+√3/2),
[(1+3)/2√3]/[(1+√3)/2],
[4/2√3]/[(1+√3)/2],
(2/√3)/[(1+√3)/2,
4/[√3(1+√3)]
sin@/cos@=1/√3,
tan@=1/√3,
tan@=tan30°,
then
@=30°,
therefore
(sin@×tan@×1+cos@)/(sin@+cos@),
(sin30°×tan30°×1+cos30°)/(sin30°+cos30°),
(1/2×1/√3+√3/2)/(1/2+√3/2),
[(1+3)/2√3]/[(1+√3)/2],
[4/2√3]/[(1+√3)/2],
(2/√3)/[(1+√3)/2,
4/[√3(1+√3)]
Humerpathan:
thanks bro
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