Math, asked by anand2005gmailcom, 10 months ago

If root 3 tan theta = 3 sin theta, find the value of sin'2 theta- cos'2 theta.



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Answers

Answered by LakshmiSirishma
1

Given,

 \sqrt{3} \: tanΘ  = 3 \sinΘ

Now,

 \sqrt{3} \tanΘ = 0

 \tanΘ = (0 \div  \sqrt{3})

 \tanΘ = 0

Θ =   0 \: degrees

Again,

3 \sinΘ = 0

 \sinΘ = (0 \div 3)

 \sinΘ = 0

Θ = 0 \: degrees

Therefore,

  \sin^{2}Θ -  \cos^{2}Θ = ({0}^{2}) -  ({1}^{2})

\sin^{2}Θ -  \cos^{2}Θ = 0 - 1

\sin^{2}Θ -  \cos^{2}Θ =  - 1

Hence,

\sin^{2}Θ -  \cos^{2}Θ =  - 1

Step-by-step explanation:

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