Question

if root 3 tan theta is equal to 1 and theta is acute find the value of sin 3 theta + cos 2 theta....


plss answer this fast ​

Answer 1

tan theta = 1/ √3

ne perpendicular= 1 and base = √3

now,

by Pythagoras therom, h= √ (1) + 3= 2

so , hypotenuse = 2

now , sin theta = perpendicular / hypotenuse

sin theta = 1/ 2

cos theta = b/ h = √3/ 2

a to question, sin 3 Theta + cos 2 theta

= 3× 1/2 + 2× √3/ 2 = 3/2 + √3=................3+ 2√3/ 2 is answer