Question

If root 3 tan theta is equal to 3 sin theta then sin square -cos square =?​

Answer 1

Answer:

Given √3tanx = 3sinx , sin²x - cos²x = ?

√3tanx - 3sinx = 0

=> √3(tanx - √3sinx) = 0

tanx - √3sinx = 0

sinx/cosx - √3sinx = 0

=> sinx ( 1 - √3cosx) = 0

=> sinx = 0 or cosx = 1/√3

=> sin²x = 0 or cos²x = 1/3

=> sin²x - cos²x = 0 -1/3 = -1/3