If root 3 tan theta is equals to 3 sin theta then find the value of sin theta
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let, theta=x
given- 3tanx=3sinx
so if we decide RHS and LHS by 3 we get
sinx=tanx
if we try another way
3tanx=3sinx
move 3 to RHS and sinx to LHS we get
tanx/sinx=1. -------(1)
tanx =sinx/cosx. ------(2)
substitute 2 in 1
sinx/casx/sinx=1
sin²x/cosx=1
sin²x=cosx
sinx=√cosx
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