if root 3 tan tita = 3 sin tita then prove that siin square tita - cos square tita =1/3
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√3tan thitha= 3sin thita
tan theta equals to root 3 sin theta
tan theta by sin theta is equals to root 3
one by cos theta is equals to root 3
cos theta is equals to one by root 3 eq 1
from question
sin squared theta minus cos squared theta equals to 1 by 3
sin sin square theta is equals to 1 minus cos square theta
therefore 1 - cos squared theta minus cos squared theta is equals to 1 by 3
1 - 2 cos square theta is equals to one by 3
from from equation 1 substitute cos theta equals to 1 by root 3
1 - 2 into one by root 3 square is equals to
1 - 2by3
that is equals to 1 by 3
therefore hence proved
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