if root 5 + 3 by root 5 minus 3 is equal to a + root 15 B find the value of a and b
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First rationalize: root 5 + root 3 divided by root 5 - root 3,
we get, (root 5 + root 3)2 / (root 5 - root 3)( root 5 + root 3)
= (8+2 root 15)/2
now compare LHS and RHS,
(given), (8+2root15) / 2 = a+root 15b
=> 2(4+ root 15) / 2 = a+root15 b [here we removed the common factor and cancelled]
=> 4+ root 15 = a+ root 15 b
therefore, the value of 'a' can be 4 and the value of 'b' can be 1 ( as any no. multiplied with one will be the no. itself)
we get, (root 5 + root 3)2 / (root 5 - root 3)( root 5 + root 3)
= (8+2 root 15)/2
now compare LHS and RHS,
(given), (8+2root15) / 2 = a+root 15b
=> 2(4+ root 15) / 2 = a+root15 b [here we removed the common factor and cancelled]
=> 4+ root 15 = a+ root 15 b
therefore, the value of 'a' can be 4 and the value of 'b' can be 1 ( as any no. multiplied with one will be the no. itself)
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