If root 5 is an irrational number. Prove that 3 - root 5 is also an irrational number
Answers
Answered by
5
Answer:
Let us assume that 3 + √5 is a rational number. Here, {(a - 3b) ÷ b} is a rational number. But we know that √5 is a irrational number. So, {(a - 3b) ÷ b} is also a irrational number.
Step-by-step explanation:
pls mark me as brainliest answer
Answered by
17
To Prove :-
- 3 - √5 is an irrational number.
Proof :-
Let us assume to the contrary, that 3 - √5 is rational.
Then, there exist co-primes a and b (b ≠ 0) such that
⇒ 3 - √5 = a/b
⇒ √5 = 3 - a/b
Here
- 3 - a/b is a rational number and √5 is an irrational number.
But, a rational number can't equal to an irrational number.
This is contradiction.
Thus, our assumption is wrong.
Therefore, 3 - √5 is an irrational number.
Hence, Proved !
Similar questions