Math, asked by HARISHBABU6787, 1 year ago

If root 5 is one of the zeros of the polynomial 5x sq - 3 root 5 x - P then find the value of p.

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Answered by gunjangupta112007
2
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Answered by Anonymous
9
\mathfrak{\huge{Answer:}}

Given polynomial is : \sf{p(x) = 5x^{2} -3\sqrt5 x - p =0}

One of the root of the polynomial is given as : \sf{\sqrt5}

Now, as the root is given to be as \sf{\sqrt5}, we can keep the value of x as \sf{\sqrt5}, in p ( x ). Do the same :

p ( \sf{\sqrt5} ) = \sf{5(\sqrt5)^{2} - 3(\sqrt5)(\sqrt5) - p = 0}

Now, try solving this formed equation further :

=》 p ( \sf{\sqrt5} ) => \sf{(5 \times 5) - (3 \times 5) = p}

Keep solving this further :

=》 p ( \sf{\sqrt5} ) => \sf{25 - 15 = p}

Last one step to go for the answer :

=》 p ( \sf{\sqrt5} ) => p = 10

There's the answer !

Thus, in p ( x ), the value of p = 10

Use to comments section to clear doubts :)
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