Question

if root 8_ root x =rootx_root4 findx=​

Answer 1

Answer:

Step-by-step explanation:

√8 = 2√2

√4 = 2

2√2 -√x = 2 - √x

2√2- 2 =2√x

2(√2 - 1) = 2√x

divide it by 2

√2 - 1 = √x

squaring both side

x = 2 +1 - 2√2

x = 3 - 2 √2

Answer 2

Answer:

HELLO

$\sqrt{8 } - \sqrt{x} = \sqrt{x} - \sqrt{4} \\ 2 \sqrt{2} - \sqrt{x} = \sqrt{x} - 2 \\ 4 \sqrt{2} = 2 \sqrt{x} \\ 2 \sqrt{2} = \sqrt{x } \\ squaring \: both \: sides \\ x =32$