If root a+root b+root c=0, (a+b-c)2=4ab
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√a+ √b +√c= 0
√a +√b = -√c
squaring
a + b + 2√ab = c
a+ b - c= -2√ab
(a+b-c)^2 = 4 ab
please check question
may be in LHS its ( a+b -c)^2
√a +√b = -√c
squaring
a + b + 2√ab = c
a+ b - c= -2√ab
(a+b-c)^2 = 4 ab
please check question
may be in LHS its ( a+b -c)^2
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