if root a + root b + root c = 0 then prove that a + b - c = 4ab
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√a+ √b +√c= 0
√a +√b = -√c
squaring
a + b + 2√ab = c
a+ b - c= -2√ab
(a+b-c)^2 = 4 ab
please check question
may be in LHS its ( a+b -c)^2
√a +√b = -√c
squaring
a + b + 2√ab = c
a+ b - c= -2√ab
(a+b-c)^2 = 4 ab
please check question
may be in LHS its ( a+b -c)^2
druthisapna:
Thank you
Answered by
4
Answer:
Step-by-step explanation:
a^(1/2) + b^(1/2) - c^(1/2) = 0
Or, a^(1/2)+b^(1/2) =c^(1/2) Squaring both sides a + b + 2 * a^(1/2) * b^(1/2) = c
Or, a + b - c = - 2 * a^(1/2) * b^(1/2). Squaring both sides (a + b - c) ^2 = 4 * a * b
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