if root of an equation 2 x square - 3qx+ 5q =0 is twice the other .find the value of q
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Let one zero be A and 2A
here, a = 2 , b = -3q , c = 5q
sum of zeroes = -b/a
A + 2A = 3q / 2
6A= 3q
q = 2A__________1
product of zeroes = c/a
Ax2A = 5q/2
2A^2 = 5(2A) /2 (USING 1)
2A^2 = 5A
A^2/A = 5/2
A = 5/2
from 1
q = 2A
q= 2X5/2
q= 5
HOPE IT HELP YOU................
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