Math, asked by siddhishelar1411, 1 year ago

if root of x square+kx+k=0are real and equal,what is value of k?

Answers

Answered by Anonymous
9
Discriminat, =0 if roots are real and equal.

So, 0 = b^2 - 4ac

0 = k^2 - 4 × 1 × k

0 = k^2 - 4k

0 = k( k - 4 )

0/k = k - 4

0 = k - 4

K = 4.

Value of k is 4.
Similar questions