if root of x square+kx+k=0are real and equal,what is value of k?
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Discriminat, =0 if roots are real and equal.
So, 0 = b^2 - 4ac
0 = k^2 - 4 × 1 × k
0 = k^2 - 4k
0 = k( k - 4 )
0/k = k - 4
0 = k - 4
K = 4.
Value of k is 4.
So, 0 = b^2 - 4ac
0 = k^2 - 4 × 1 × k
0 = k^2 - 4k
0 = k( k - 4 )
0/k = k - 4
0 = k - 4
K = 4.
Value of k is 4.
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