If root x is an irrational number then x is what
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Prove that if x is irrational, then sqrt(x) is irrational. Then I end up with x=m2n2 for m,n to be integers and n does not equal 0. Is it careless to be done with the proof since we are saying that x=m2n2 is a rational number therefore the contrapositive is true, therefore the original statement is also true?
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same
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