Question

If root2=1.41 and root5=2.24 find the value of 3/(8root2+5root5)+2/(8root2-5root5) solve gt.9th

Answer 1

solve by factorization

3/(8√2+5√5) + 2/(8√2-5√5) => [3*(8√2-5√5)]/[(8√2+5√5)*(8√2-5√5)] + [2*(8√2+5√5)]/[(8√2-5√5)*(8√2+5√5)]

(a+b)*(a-b) = a^2-b^2

Apply this formula to denominator

=> [3*(8√2-5√5)]/[128-125] + [2*(8√2+5√5)]/[128-125]

=>(8√2-5√5) + (2/3)*[8√2+5√5]

=>13_1/3√2 -5/3√5

I expect you to place the values and find the answer