Question

If root2 is one of the solution of quadratic equation kx2+root 2 x- 4=0 then find the value of k?

Answer 1

Zero = √2

Polynomial = kx^2 + √2 x - 4 = 0

p(√2) = 0

=> k(√2)^2 + √2(√2) - 4 = 0

=> 2k + 2 - 4 = 0

=> 2k = 2

=> k = 1