If root2+ root3/3 root2-2 root3= a+b root6 then find the value of a and b
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(√2 + √3)/(3√2 - 2√3) = a - b√6
(√2 + √3)(3√2 + 2√3) / (3√2 - 2√3)(3√2 + 2√3) = a - b√6
(6 + 3√6 + 2√ 6 + 6) / 6 = a - b√6
(12 + 5√6) / 6 = a - b√6
2 + 5/√6 = a - b√6
2 + 5√6/6 = a - b√6
a = 2
b = -5/6
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√2 + √3)/(3√2 - 2√3) = a + b√6
(√2 + √3)(3√2 + 2√3) / (3√2 - 2√3)(3√2 + 2√3) = a + b√6
(6 + 3√6 + 2√ 6 + 6) / 6 = a + b√6
(12 + 5√6) / 6 = a + b√6
2 + 5/√6 = a + b√6
2 + 5√6/6 = a + b√6
a = 2
b = -5/6
(√2 + √3)(3√2 + 2√3) / (3√2 - 2√3)(3√2 + 2√3) = a + b√6
(6 + 3√6 + 2√ 6 + 6) / 6 = a + b√6
(12 + 5√6) / 6 = a + b√6
2 + 5/√6 = a + b√6
2 + 5√6/6 = a + b√6
a = 2
b = -5/6
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