If root3 + root2= x find root3- root2
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Answer:
√3+√2=x
multiply both side by (√3-√2)
=> (√3+√2)(√3-√2)=x(√3-√2)
=> (√3)^2-(√2)^2=x(√3-√2)
=> 3-2=x(√3-√2)
=> x(√3-√2)=1
=> √3-√2=1/x
so , √3-√2=1/x
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