If root3 tan theta = 3 sin theta , then find the value for sin theta
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root3 tanx=3 sinx
sinx/cosx=root3 sinx
1/cosx=root3
1/root3= cosx
now now in right angle triangle cos is base, sin is altitude,so applying cos in triangle cosx=1/root3
we get triangle third side by pythagoras therom
as.
root3 square+1 square=(?)square
3+1=(?)square
4=(?)square
2=?
so here sin=1/2
sinx/cosx=root3 sinx
1/cosx=root3
1/root3= cosx
now now in right angle triangle cos is base, sin is altitude,so applying cos in triangle cosx=1/root3
we get triangle third side by pythagoras therom
as.
root3 square+1 square=(?)square
3+1=(?)square
4=(?)square
2=?
so here sin=1/2
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