Math, asked by SinchanaVPoojary, 6 months ago

if root3 tanQ=1andQ is an acute angle find the value of sin3Q+cos2Q

Answers

Answered by sandy1816

3

√3tanQ=1

➡tanQ=1/√3

➡Q=Π/6

sin3Q+cos2Q

=sin3Π/6+cos2Π/6

=sinΠ/2+cosΠ/3

=1+1/2

=3/2

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