if root3 tanQ=1andQ is an acute angle find the value of sin3Q+cos2Q
Answers
Answered by
3
√3tanQ=1
➡tanQ=1/√3
➡Q=Π/6
sin3Q+cos2Q
=sin3Π/6+cos2Π/6
=sinΠ/2+cosΠ/3
=1+1/2
=3/2
Similar questions
Science,
2 months ago
Environmental Sciences,
2 months ago
Math,
2 months ago
Accountancy,
4 months ago
Biology,
4 months ago
Math,
10 months ago