If root5/3 and -5/3 are two zeros of the polynomial 3xrise to 4 +6xcube-2xsqaure_10x-5
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Answer: -1,-1
Step-by-step explanation:
Since, √5/3 and -√5/3 are two zeroes of p(x),
∴ (x-√5/3) and (x+√5/3) are the factors of p(x)
⇒(x-√5/3)(x+√5/3)=x²-5/3
Dividing p(x) by x²-5/3 ( Remainder will always be zero in such questions)
(3x∧4+6x³-2x²-10x-5)/(x²-5/3)
= 3x²+6x+3
Now find the roots of above equation,
x= -b±√b²-4ac/2a
=-1,-1
Please let me know if you need complete calculations...
hope this helps!!!
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