Question

If roots of eq 3x^2 +kx +12=0 are real then find k

Answer 1

Answer:

K > 12

Step-by-step explanation:

Discriminant = b^2 - 4ac

If discriminant is greater than 0 then roots are real

So

K^2 - 4 * 3 * 12 > 0

K^2 - 144 > 0

K^2 > 144

K > 12

Ps. If you meant if the roots are real and same then it will be k = 12 as discriminant = 0 in that case but since it is just real. The ans is k > 12