if roots of equation are -3 and -2 then form quadratic equation with variable y
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Answer:
y^2+5y+6
Step-by-step explanation:
alpha = -3
beta = -2
alpha + beta = -5
alpha×beta = 6
sub in this equation
y^2 -(alpha + beta)y + alpha×beta
y^2-(-3-2)y+(-3)(-2)
y^2+5y+6
Here is the required equation...
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