Question

if roots of equation within bracket a minus b bracket close x square + within bracket b minus C bracket close X + c minus a equals to zero are equal then b + c = ?

Answer 1

hope this helps you .

Answer 2

Answer:2a

Step-by-step explanation:

given (a-b)x²+(b-c)x+(c-a)=0

because roots are equal then D=0

⇒b²-4ac=0

⇒(b-c)²-4(a-b)(c-a)=0

⇒b²+c²-2bc-4ac+4a²+4bc-4ab = 0

⇒b²+c²+2bc-4ab-4ac+4a²=0

⇒(b+c)²-2*2a(b+c)+(2a)²=0

⇒{(b+c)-2a}²=0

⇒b+c= 2a