if roots of equation x^2-4x+3=0 is the solution of equation x+ay=4 and bx+y=7 then find a and b
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Since α,β are the root of equation x2−3x+5=0
So, α2−3α+5=0
β2−3β+5=0
∴α2−3α=−5
β2−3β=−5
Putting in (α2−3α+7) & (β2−3β+7) ....... (1)
−5+7,−5+7
∴ 2 and 2 are the roots
∴ The required equation is x2−4x+4=0
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