IF roots of equation x²+px+12=0 are in ratio 1:3.find the valve of p
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let first root is A
then second root = 3A
sum of roots = A + 3A =4A= -p
product of roots = 3A^2= 12
》A^2 = 4
》 A = 2
4A = -p
p = -8
then second root = 3A
sum of roots = A + 3A =4A= -p
product of roots = 3A^2= 12
》A^2 = 4
》 A = 2
4A = -p
p = -8
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