Question

If roots of equation x²+px+12=0 are in the ratio 1:3 find the valve of p

Answer 1

first root is A
then second root = 3A
sum of roots = A + 3A =4A= -p
product of roots = 3A^2= 12
》A^2 = 4
》 A = 2

4A = -p
p = -8

Answer 2

12/1=x*3x
${x}^{2} = 4$
X=+2,-2