If roots of euation (a square +b square) x square +2(bc-ad)x+ c square +d square=0 if roots are real and equal show ac+bd=0
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Since the roots are real and equal, the discriminant must be zero.
The discriminant here is
( 2( bc - ad) )² - 4 ( a² + b² ) ( c² + d² )
= 4 ( b²c² + a²d² - 2abcd ) - 4 ( a²c² + a²d² + b²c² + b²d² )
= - 4 ( a²c² + b²d² + 2abcd )
= -4 ( ac + bd )²
So this must be zero, and so
ac = bd = 0
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