Math, asked by nirja09, 8 months ago

If roots of px2 + 6x + 1 = 0 are real, find p.

Answers

Answered by ujjairrahman456

4

Answer:

p>= 9

Step-by-step explanation:

here a=9,b=6,c=1

The given equation will have real roots

If b*2-4ac>=0

=6*6-4(p)(1)>=0

=36-4p>=0

=36>=4p

=p>=9

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