Math, asked by udaynaik56659, 1 year ago

If roots of px²+6x+1=0 are real,find p

Answers

Answered by Ijack228
3
If the roots of the equation are real
discriminant ≥ 0
=> b² - 4ac ≥ 0
=> 6² - 4 x p x 1 ≥ 0
=> 36 - 4p ≥ 0
=> 36 ≥ 4p
=> 36/4 ≥ p
=> 9 ≥ p
Hence p ≤ 0
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