if roots of the equation 5x^2 + 2x + p(p-2)= 0 are of opposite sign then integral value of p is
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so two integral values of p
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(4p−p2−5)x2−(2p−1)x+3p=0=f(x)
Roots lie on either side of unity.
∴f(1)>0 as (4p−p2−5<0)⟹(4p−p2−5)12−(2p−1)1+3p>0⟹−p2+5p−4>0⟹p2−5p+4<0⟹(p−4)(p−1)<0⟹p∈(1,4)∴p=2,3
So two integral values of p.
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