Question

if roots of the equation (a-b)x²+(b-c)x+(c-a)=0 are equal then b+c=​

Answer 1

Step-by-step explanation:

use ,

$b {}^{2} = 4ac \\( b - c) {}^{2} = 4 (a - b) (c - a)$

$b {}^{2} + c {}^{2} - 2bc = 4ac - 4a {}^{2} - 4bc + 4ab$

taking -4bc to the left side

$(b + c) {}^{2} = 4a(c + b - a )$

TAKING SQUARE ROOT BOTH SIDES

$b + c = 2 \sqrt{a(b + c - a)}$