Question

If roots of the equation (b-c)x2+(c-a)x+(a-b)=0,are equal then find 2b=a+c

Answer 1

One of the root of equation is 1 and the same is other as given in the statement
Product of roots = 1= a-b/b-c
B-c=a-b
2b= a+c
Hence proved
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