Question

if roots of the equation :x^2 +(k+1)x+3 =0 are equal in magnitude but opposite in sign, then k is​

Answer 1

Answer:

let one zero be y

other zero= -y

sum of zeroes= -b/a

y-y= -(k+1)/1

0= -k-1

k= -1

Step-by-step explanation:

Answer 2

Answer:

k=-1

Step-by-step explanation:

let one zero be y

other zero= -y

sum of zeroes= -b/a

y-y= -(k+1)/1

0= -k-1

k= -1