Question

If roots of the quadratic equation ax^2-6x+1=0 are equal then the value of a

Answer 1

Step-by-step explanation:

3x ^2 +ax−2=0

Since, one root is 1, then x=1

⇒ 3(1) ^2 +a(1)−2=0

⇒ 3+a−2=0

⇒ a+1=0

⇒ a=−1

⇒ Now, it is given that ax ^2+6ax−b=0 has equal roots.

∴ b ^2 −4ac=0

⇒ (6a) ^2 −4(a)(−b)=0

⇒ 36a^ 2+4ab=0

⇒ 36(−1)^ 2 +4(−1)b=0 [ Substitutinga=−1 ]

⇒ 36−4b=0

⇒ 4b=36

∴ b=9

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