Question

if roots of the quadratic equation is x^2-2(m+a)x+m^2=0 are real and equal then find the value of m​

Answer 1

Answer:

please let know what to expect and Friday this and the latest version

Answer 2

Answer:

Given

Roots of quadratic equation x²-2(m+a)x+m²=0 are real and equal

To find

Value of m

Solution

When the roots of a quadratic equation are equal, then

b²-4ac = 0 --------(1)

In the quadratic equation

a = 1 (Coefficient of the x²)

b = -2(m+a) (Coefficient of x)

c = m²

Now we put the value of a,b and c in equation 1

[-2(m+a)]² - 4(1)(m²) = 0

4(m+a)² - 4m² = 0

4(m²+2am+a²) - 4m² = 0

4m²+ 2am + a² - 4m² = 0

2am + a² = 0

2am = -a²

m = -a²/2a

m = -a/2

Therefore value of m is -a/2.

Hope it helps you.

Mark as brainliest please.