if roots of tue quadratic equation (a-b)x^2+(b-c)x+(c-a=0 are equal ,prove that 2a=b+c
Answers
Answered by
1
if roots are equal then D=0
b²-4ac=0
apply this frmla and solve it
sraddhavaranasi22:
ya..i used but i am not able to get the ans
then i can give u later bcs i m in music consart
ok great..all the best thank u
Answered by
3
Answer:
Roots are equal
=> discriminant = 0
=> (b-c)² - 4(a-b)(c-a) = 0
=> (b-c)² - 4ac + 4a² + 4bc - 4ab = 0
=> [ (b-c)² + 4bc ] - 4a(b+c) + 4a² = 0
=> (b+c)² - 4a(b+c) + 4a² = 0
=> ( b + c - 2a )² = 0
=> b + c - 2a = 0
=> 2a = b + c
Hello. Hope this helps. Plz mark it brainliest. Have a good day!
Ya sure bro!! I maroed u already!! Thanks a lot!! Have a good day too!!
ty
Similar questions