if roots of x^2+ px + 40 =0 are in ratio 2:5 then find value of p
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Answer:
roots are (4, 10) or ( -4, -10)
Step-by-step explanation:
Let the roots of the equation be 2y and 5y
we know
sum of the roots of a equation = -b/a
product of the roots of the equation = c/a
therefore 2y + 5y = -p
7y = -p
p = -7y
and (2y)(5y) = 40
10y² = 40
y² = 4
y = 2 or -2
if y = 2
roots are 4 and 10
if y = -2
roots are -4 and -10
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